[Python] How to avoid repeated checks for an optional callback in a Python for loop?

Discussão em 'Python' iniciado por Stack, Fevereiro 5, 2025.

  1. Stack

    Stack Membro Participativo

    Let’s say I have a function download() that takes an optional on_progress callback. Inside the function, I iterate over some data and call on_progress(i) if the callback is provided. My current implementation looks like this:

    def download(on_progress: Callable | None):
    data = requests.get(“exampleurl.com”)
    for i in data.iter_content():
    if on_progress:
    on_progress(i)


    However, the if on_progress check inside the loop feels inefficient and repetitive. Is there a more Pythonic way to avoid this check on every iteration while still allowing the on_progress callback to be optional?

    Let me know if you want me to add extra details like performance concerns or specific use cases!

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