[Python] How does zip(*[iter(s)]*n) work in Python?

Discussão em 'Python' iniciado por Stack, Fevereiro 1, 2025.

  1. Stack

    Stack Membro Participativo

    s = [1,2,3,4,5,6,7,8,9]
    n = 3

    list(zip(*[iter(s)]*n)) # returns [(1,2,3),(4,5,6),(7,8,9)]


    How does zip(*[iter(s)]*n) work? What would it look like if it was written with more verbose code?


    This is a technique used for splitting a list into chunks of equal size - see that question for a general overview of the problem.

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