[Python] How does one compare the contents of two lists of non-hashable objects in python...

I have two lists of numpy arrays, and I want to check if the two lists have the same set of numpy arrays. If they have the same arrays in a different order, I still want it to return true. The numpy arrays in each list are not all the same shape, so I can't use anything that would rely on that. As an example, let's just set

list_1 = [numpy.array([1, 2]), numpy.array([3])]
list_2 = [numpy.array([3]), numpy.array([1, 2])]


as an example of something that should return true when compared. The order of elements should matter within the numpy array, so

list_3 = [numpy.array([2, 1]), numpy.array([3])]


should return false when compared with both of list_1 and list_2.

I can't use set(list_1) == set(list_2), which is what I would normally try, because I get TypeError: unhashable type: numpy.ndarray. My backup solution was to try the following function:

def contents_equal(list_1, list_2):
for array in list_1:
if array not in list_2:
return False
for array in list_2:
if array not in list_1:
return False
return True


Unfortunately, this did not work either. I got the following error on the line if array not in list_2:

ValueError: The truth value of an array with more than one element is ambiguous. Use a.any() or a.all()

I tried another solution with a.all(), as it suggested:

def contents_equal(list_1, list_2):
if [array not in list_2 for array in list_1].any():
return False
if [array not in list_1 for array in list_2].any():
return False
return True


This one felt less readable to me, but I figured if it worked, it worked. Unfortunately, it didn't work. I got the same ValueError on the if statement. I'm not sure what to try from here, or even why my solution isn't working. I'm not evaluating any list as a boolean in either solution as far as I can tell, which seems to be what the error is complaining about. Can anyone enlighten me?

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