[Python] How Do We Use numpy to Create a Matrix of all permutations of three separate value...

Discussão em 'Python' iniciado por Stack, Abril 16, 2025.

  1. Stack

    Stack Membro Participativo

    I want to make a pandas dataframe with three columns, such that the rows contain all permutations of three columns, each with its own range of values are included. In addition, I want to sort them asc by c1, c2, c3.

    For example, a = [0,1,2,3,4,5,6,7], b = [0,1,2], and c= [0,1]. The result I want looks like this:

    c1 c2 c3
    0 0 0
    0 0 1
    0 1 0
    0 1 1
    0 2 0
    0 2 1
    1 0 0
    1 0 1
    1 1 0
    ...
    7 2 0
    7 2 1


    I keep trying to fill columns using numpy.arange, i.e., numpy.arange(0,7,1) for c1. But that doesn't easily create all the possible rows. In my example, I should end up with 8 * 3 * 2 = 48 unique rows of three values each.

    I need this to act as a mask of all possible value combinations from which I can merge a sparse matrix of experimental data.

    Does anyone know how to do this? Recursion?

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