[Python] How do I return value of a dictionary as a string instead of a integer? [closed]

Trying to understand what the issue is with the following code:

mbox-short.txt is a email list and a code checks for the # of messages from iupui.edu. It is supposed to be 8 but the code checker says it is supposed to be '8' instead. How do I modify the code so the checker will confirm this is ok?

Here is the code:

with open("mbox-short.txt", "r") as filename:
message_count = {}
messages = filename.readlines()

for message in messages:
words = message.split()
#print(words)
if len(words) > 1 and '@' in words[1] and words[0]=="From":
email = words[1]
address = email.split('@')[1]
if address in message_count:
message_count[address] += 1
else:
message_count[address] = 1
for address, count in message_count.items():
print(f"{address}:{count} messages")


AFTER COMPILING, it gives:

uct.ac.za:6 messages
media.berkeley.edu:4 messages
umich.edu:7 messages
iupui.edu:8 messages
caret.cam.ac.uk:1 messages
gmail.com:1 messages


error checker complaint:

Result Actual Value Expected Value Notes
Fail 8 '8' message_count['iupui.edu']
Pass 6 6 len(message_count)


Any idea why? Please see above. Checker wants '8' instead of 8 (see Fail).

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