I want to check if a program is running or not, so I searched and I tried this , in this way: import psutil if "notepad.exe" in (p.name() for p in psutil.process_iter()): print('program is running') else: print('not running') but I get this error: During handling of the above exception, another exception occurred: Traceback (most recent call last): File "~/temp.py", line 2, in <module> if "notepad.exe" in (p.name() for p in psutil.process_iter()): File "~/temp.py", line 2, in <genexpr> if "notepad.exe" in (p.name() for p in psutil.process_iter()): File "~\Python\Python38-32\lib\site-packages\psutil\__init__.py", line 630, in name name = self._proc.name() File "~\Python\Python38-32\lib\site-packages\psutil\_pswindows.py", line 750, in name return os.path.basename(self.exe()) File "~\Python\Python38-32\lib\site-packages\psutil\_pswindows.py", line 681, in wrapper raise convert_oserror(err, pid=self.pid, name=self._name) psutil.AccessDenied: psutil.AccessDenied (pid=6836) Process finished with exit code 1 am I doing something wrong with this simple code? or is there another alternative way? EDIT: sorry, i forgot to mention im on windows, not linux, can u give me solutions for windows platform? Continue reading...