I want to get the coordinates of a number of points that together form an octagon. For a circle this is done easily as follows: import numpy as np n = 100 x = np.cos(np.linspace(0, 2 * np.pi, n)) y = np.sin(np.linspace(0, 2 * np.pi, n)) coordinates = list(zip(x, y)) By changing n I can increase/decrease the "angularity". Now I want to do the same for an octagon. I know that an octagon has 8 sides and the angle between each side 45 degrees. Let's assume that the perimeter of the octagon is 30.72m. Each side has therefore a length of 3.79m. perimeter = 30.72 n_sides = 8 angle = 45 How can I get n coordinates that represent this octagon? Continue reading...
