[Python] FlushError: new instance conflicts with persistent instance

Discussão em 'Python' iniciado por Stack, Abril 9, 2025.

  1. Stack

    Stack Membro Participativo

    I have some problems when I try to update information in some tables. For example, I have this table:

    class Channel(rdb.Model):
    rdb.metadata(metadata)
    rdb.tablename("channels")

    id = Column("id", Integer, primary_key=True)
    title = Column("title", String(100))
    hash = Column("hash", String(50))
    runtime = Column("runtime", Float)

    items = relationship(MediaItem, secondary="channel_items", order_by=MediaItem.position, backref="channels")


    And I have this code:

    def insertXML(channels, strXml):
    channel = Channel()
    session = rdb.Session()
    result = ""

    channel.fromXML(strXml)
    fillChannelTemplate(channel, channels)

    rChannel = session.query(Channel).get(channel.id)
    for chan in channels:
    if rChannel.id == channel.id:
    rChannel.runtime = channel.runtime
    for item in channel.items:
    if item.id == 0:
    rChannel.items.append(item)


    When I do "rChannel.items.append(item)", I got this error:

    "FlushError: New instance Channel at 0xaf6e48c with identity key
    zeppelinlib.channel.ChannelTest.Channel , (152,) conflicts with
    persistent instance Channel at 0xac2e8ac"


    However, this instruction is working "rChannel.runtime = channel.runtime".

    Continue reading...

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