[Python] Find last match with python regular expression

I want to match the last occurrence of a simple pattern in a string, e.g.

list = re.findall(r"\w+ AAAA \w+", "foo bar AAAA foo2 AAAA bar2")
print "last match: ", list[len(list)-1]


However, if the string is very long, a huge list of matches is generated. Is there a more direct way to match the second occurrence of " AAAA ", or should I use this workaround?

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