[Python] Fastest way to eliminate specific dates from pandas dataframe

Discussão em 'Python' iniciado por Stack, Março 18, 2025.

  1. Stack

    Stack Membro Participativo

    I'm working with a large data frame and I'm struggling to find an efficient way to eliminate specific dates. Note that I'm trying to eliminate any measurements from a specific date.

    Pandas has this great function, where you can call:

    df.ix['2016-04-22']


    and pull all rows from that day. But what if I want to eliminate all rows from '2016-04-22'?

    I want a function like this:

    df.ix[~'2016-04-22']


    (but that doesn't work)

    Also, what if I want to eliminate a list of dates?

    Right now, I have the following solution:

    import numpy as np
    import pandas as pd
    from numpy import random

    ###Create a sample data frame

    dates = [pd.Timestamp('2016-04-25 06:48:33'), pd.Timestamp('2016-04-27 15:33:23'), pd.Timestamp('2016-04-23 11:23:41'), pd.Timestamp('2016-04-28 12:08:20'), pd.Timestamp('2016-04-21 15:03:49'), pd.Timestamp('2016-04-23 08:13:42'), pd.Timestamp('2016-04-27 21:18:22'), pd.Timestamp('2016-04-27 18:08:23'), pd.Timestamp('2016-04-27 20:48:22'), pd.Timestamp('2016-04-23 14:08:41'), pd.Timestamp('2016-04-27 02:53:26'), pd.Timestamp('2016-04-25 21:48:31'), pd.Timestamp('2016-04-22 12:13:47'), pd.Timestamp('2016-04-27 01:58:26'), pd.Timestamp('2016-04-24 11:48:37'), pd.Timestamp('2016-04-22 08:38:46'), pd.Timestamp('2016-04-26 13:58:28'), pd.Timestamp('2016-04-24 15:23:36'), pd.Timestamp('2016-04-22 07:53:46'), pd.Timestamp('2016-04-27 23:13:22')]

    values = random.normal(20, 20, 20)

    df = pd.DataFrame(index=dates, data=values, columns ['values']).sort_index()

    ### This is the list of dates I want to remove

    removelist = ['2016-04-22', '2016-04-24']


    This for loop basically grabs the index for the dates I want to remove, then eliminates it from the index of the main dataframe, then positively selects the remaining dates (ie: the good dates) from the dataframe.

    for r in removelist:
    elimlist = df.ix[r].index.tolist()
    ind = df.index.tolist()
    culind = [i for i in ind if i not in elimlist]
    df = df.ix[culind]


    Is there anything better out there?

    I've also tried indexing by the rounded date+1 day, so something like this:

    df[~((df['Timestamp'] < r+pd.Timedelta("1 day")) & (df['Timestamp'] > r))]


    But this gets really cumbersome and (at the end of the day) I'll still be using a for loop when I need to eliminate n specific dates.

    There's got to be a better way! Right? Maybe?

    Continue reading...

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