[Python] extracting days from a numpy.timedelta64 value

Discussão em 'Python' iniciado por Stack, Janeiro 29, 2025.

  1. Stack

    Stack Membro Participativo

    I am using pandas/python and I have two date time series s1 and s2, that have been generated using the 'to_datetime' function on a field of the df containing dates/times.

    When I subtract s1 from s2


    s3 = s2 - s1
    ​

    I get a series, s3, of type


    timedelta64[ns]
    ​

    0 385 days, 04:10:36
    1 57 days, 22:54:00
    2 642 days, 21:15:23
    3 615 days, 00:55:44
    4 160 days, 22:13:35
    5 196 days, 23:06:49
    6 23 days, 22:57:17
    7 2 days, 22:17:31
    8 622 days, 01:29:25
    9 79 days, 20:15:14
    10 23 days, 22:46:51
    11 268 days, 19:23:04
    12 NaT
    13 NaT
    14 583 days, 03:40:39


    How do I look at 1 element of the series:


    s3[10]
    ​

    I get something like this:


    numpy.timedelta64(2069211000000000,'ns')
    ​

    How do I extract days from s3 and maybe keep them as integers(not so interested in hours/mins etc.)?

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