[Python] Dismiss a kivy popup thats created outside the function thats dismissing it

Im creating a kivy popup with all available drives. The idea is to click a drive button and than have that directory open in filechooser widget. The only issue is I need to dismiss the drive popup once the directory is opened but I cant reference that popup within my drive function. I have tried to create the popup at the top of the class but that did not work either.

def filebtn(self):

global popup
from functools import partial

popup_1 = Popup(title="Select drive to access", size_hint=(0.7, 0.7))
content_layout = BoxLayout(orientation='vertical', spacing=10)
box_layout = BoxLayout(size=(500, 500))

if platform == 'win':

print('platform is windows')

drives = []
for letter in "ABCDEFGHIJKLMNOPQRSTUVWXYZ":
drive_path = f"{letter}:\\"
if os.path.exists(drive_path):
drives.append(drive_path)
print(drives)

for item in drives:
btn = Button(text=item)
btn.bind(on_release=partial(self.get_drive, item))

content_layout.add_widget(btn)

popup_1.add_widget(content_layout)

popup_1.open()

else:
popup.open()

def get_drive(self,item,instance):

print(f"Button text: {item}")
MyFileChooser.rootpath = item

popup = Popup(title='Select Files and click attach when selected, click outside the box to close',
content=MyFileChooser(),
# dont need () because they already called the function at the top of class with mc = Myfilechooser()
size_hint=(0.7, 0.7))
popup.bind(on_dismiss=lambda attached: self.attach_called())


popup.open()
popup_1.dismiss() # problem here

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