[Python] Decorating Hex function to pad zeros

Discussão em 'Python' iniciado por Stack, Julho 3, 2025.

  1. Stack

    Stack Membro Participativo

    I wrote this simple function:

    def padded_hex(i, l):
    given_int = i
    given_len = l

    hex_result = hex(given_int)[2:] # remove '0x' from beginning of str
    num_hex_chars = len(hex_result)
    extra_zeros = '0' * (given_len - num_hex_chars) # may not get used..

    return ('0x' + hex_result if num_hex_chars == given_len else
    '?' * given_len if num_hex_chars > given_len else
    '0x' + extra_zeros + hex_result if num_hex_chars < given_len else
    None)


    Examples:

    padded_hex(42,4) # result '0x002a'
    hex(15) # result '0xf'
    padded_hex(15,1) # result '0xf'


    Whilst this is clear enough for me and fits my use case (a simple test tool for a simple printer) I can't help thinking there's a lot of room for improvement and this could be squashed down to something very concise.

    What other approaches are there to this problem?

    Continue reading...

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