[Python] Convert a Python float value to Turbo Pascal's 48‑bit real in Python

I am trying to convert a floating number to 48‑bit Real (from Borland Pascal) in Python. I have found this method written in C# (I think):

static byte[] DoubleToReal48(double d)
{
byte[] r = new byte[6];

long bits = BitConverter.DoubleToInt64Bits(d);
bool negative = ((bits >> 63) & 1) != 0;
long exponent = ((bits >> 52) & 0x7FF) - 1023;
long mantissa = bits & 0xFFFFFFFFFFFFFL;

long raw = (negative ? 1 : 0);
raw = (raw << 39) | (mantissa >> 13);
raw = (raw << 8) | ((exponent + 129) & 0xFF);

for (int k = 0; k < 6; k++)
{
r[k] = (byte)(raw & 0xFF);
raw >>= 8;
}
return r;
}


I don’t know C#, so I’m having a hard time translating it to Python. Can anyone help me? Or perhaps there is a better way?

I have found this but it seems to only convert 48‑bit Real to double, not the other way around as I need.

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