I'm trying to get 10 fold confusion matrix for any models (Random forest, Decision tree, Naive Bayes. etc) I can able to get each confusion matrix normally if I run for normal model as below shown: from sklearn.model_selection import train_test_split from sklearn import model_selection from sklearn.ensemble import RandomForestClassifier from sklearn.metrics import roc_auc_score # implementing train-test-split X_train, X_test, y_train, y_test = train_test_split(X, y, test_size=0.34, random_state=66) # random forest model creation rfc = RandomForestClassifier(n_estimators=200, random_state=39, max_depth=4) rfc.fit(X_train,y_train) # predictions rfc_predict = rfc.predict(X_test) print("=== Confusion Matrix ===") print(confusion_matrix(y_test, rfc_predict)) print('\n') print("=== Classification Report ===") print(classification_report(y_test, rfc_predict)) Out[1]: === Confusion Matrix === [[16243 1011] [ 827 16457]] === Classification Report === precision recall f1-score support 0 0.95 0.94 0.95 17254 1 0.94 0.95 0.95 17284 accuracy 0.95 34538 macro avg 0.95 0.95 0.95 34538 weighted avg 0.95 0.95 0.95 34538 But, now I want to get confusion matrix for 10 cv fold. How should I approach or do it. I tried this but not working. # from sklearn import cross_validation from sklearn.model_selection import cross_validate kfold = KFold(n_splits=10) conf_matrix_list_of_arrays = [] kf = cross_validate(rfc, X, y, cv=kfold) print(kf) for train_index, test_index in kf: X_train, X_test = X[train_index], X[test_index] y_train, y_test = y[train_index], y[test_index] rfc.fit(X_train, y_train) conf_matrix = confusion_matrix(y_test, rfc.predict(X_test)) conf_matrix_list_of_arrays.append(conf_matrix) Dataset consists of this dataframe: Temperature Series Parallel Shading Number of cells Voltage(V) Current(I) I/V Solar Panel Cell Shade Percentage IsShade 30 10 1 2 10 1.11 2.19 1.97 1985 1 20.0 1 27 5 2 10 10 2.33 4.16 1.79 1517 3 100.0 1 30 5 2 7 10 2.01 4.34 2.16 3532 1 70.0 1 40 2 4 3 8 1.13 -20.87 -18.47 6180 1 37.5 1 45 5 2 4 10 1.13 6.52 5.77 8812 3 40.0 1 Continue reading...