[Python] Computing a Confidence Interval for a Gaussian-Weighted Integral

Discussão em 'Python' iniciado por Stack, Março 2, 2025.

  1. Stack

    Stack Membro Participativo

    Requirement: Provide a 96% confidence interval for [​IMG].


    I used numerical integration (e.g., Monte Carlo integration) to approximate the value of I.

    Here is how I could use Monte Carlo integration:

    • Generate a large number of random samples (xi) from a suitable distribution (e.g., a normal distribution with a large standard deviation).
    • Calculate the function values [​IMG] for each sample.
    • Estimate the integral by taking the average of these function values.
    • Repeat the process multiple times to get a sample of integral estimates.

    import numpy as np
    import scipy.integrate as integrate

    def integrand(x):
    return np.exp(-x**2) * np.abs(np.sin(x))

    # Numerical integration using scipy.integrate.quad
    result, error = integrate.quad(integrand, -np.inf, np.inf)
    print(f"Numerical integration result: {result}")

    # Monte Carlo integration
    def monte_carlo_integral(num_samples):
    samples = np.random.normal(0, 5, num_samples) # adjust standard deviation as needed
    function_values = integrand(samples)
    return np.mean(function_values)*np.sqrt(2*np.pi)*5 # adjust multiplier based on standard deviation.

    num_iterations = 1000
    num_samples = 10000
    estimates = [monte_carlo_integral(num_samples) for i in range(num_iterations)]

    mean_estimate = np.mean(estimates)
    std_estimate = np.std(estimates)

    print(f"Monte Carlo mean estimate: {mean_estimate}")
    print(f"Monte Carlo standard deviation estimate: {std_estimate}")

    • Currently, I had a sample of estimates for I.
    • I could use this sample to calculate a confidence interval.
    • Since I had a reasonably large number of iterations (1000), I could use the normal distribution to approximate the confidence interval.
    • Confidence level: 96%.
    • z-score for 96% confidence:
      • Find the z-score corresponding to (1 + 0.96) / 2 = 0.98.
      • Using a z-table or calculator, the z-score is approximately 2.05.
    • Margin of error (E): [​IMG]
    • Confidence interval: (mean_estimate - E, mean_estimate + E)

    z_score = 2.05
    margin_of_error = z_score * (std_estimate / np.sqrt(num_iterations))
    confidence_interval = (mean_estimate - margin_of_error, mean_estimate + margin_of_error)

    print(f"96% Confidence Interval: {confidence_interval}")


    At the moment, I don't know how to solve this problem mathematically, so I hope anyone can support me to analyze it.

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