I can't identify the problem in my code that is causing my answers to differ from the correct answers.Correct answers- 157 for k and 973622 for m.My answer- 148 for k and 989329 for m. Issue: The file contains a sequence of integers. The sequence elements can take integer values from -1,000,000 to 1,000,000 inclusive. Determine the number of triples of elements in which only two of the three elements of the triple are five-digit numbers, and the sum of the elements of the triple is not more than the maximum element of the sequence ending in 29. Write down two numbers in the answer.: first, the number of triples found, and then the maximum of the sums of such triples. In this problem, a triple refers to three consecutive elements of a sequence. Code: f= open('file.txt') a=[int(x) for x in f] l=len(a) s=[] m=-10000000 k=0 for n in range(l-1): if a[n] % 100 == 29: m = max(m, a[n]) if (100000>abs(a[n])>9999 and 100000>abs(a[n+1])>9999 and not(100000>abs(a[n+2])>9999)) or (100000>abs(a[n])>9999 and 100000>abs(a[n+2])>9999 and not(100000>abs(a[n+1])>9999)) or (100000>abs(a[n+1])>9999 and 100000>abs(a[n+2])>9999 and not(100000>abs(a[n])>9999)): if m>= a[n]+a[n+1]+a[n+2]: k+=1 s+=[a[n]+a[n+1]+a[n+2]] print(k,m,s) I know that checking for five digits of a number is bad, but this is for clarity and simplicity of the code.I want to understand why my code is not working and how to fix it.Thank you for your attention the code given in the response to the issue: count = 0 m = 0 f = open('17.txt') l = [int(i) for i in f] max_dvy = 0 for i in range(len(l)): if l % 100 == 29: max_dvy = max(max_dvy, l) for i in range(len(l) - 2): c = 0 s = [l, l[i+1], l[i+2]] for x in s: if 9999 < abs(x) < 100000: c += 1 if c == 2 and sum(s) <= max_dvy: m = max(m, (l + l[i+1] + l[i+2])) count += 1 print(count, m) Continue reading...