[Python] Cannot infer type for @indie.param.context [closed]

Indie indicator getting this error during compile

Error: [internal] can not infer type for @indie.param.context, use @indie.param decorator with following types: int, float, string, str, time_frame, source, bool, color
​

This happens when I try to declare ctx as an input parameter using @param.context("ctx"). Here's a minimal reproduction:

# indie:lang_version = 4
import math
from indie import indicator, param, plot, color, SeriesF, MutSeriesF, MainContext
from indie.algorithms import Sum

@indicator("Autocorrelation Indicator")
@param.context("ctx") # !!=ERROR=!!
@param.source("src", title="Source")
@param.int("length", default=20, title="Length")
@param.bool("test_signal", default=False, title="Use test signal")
class Main(MainContext):
def __init__(self, ctx: MainContext, src: SeriesF, length: int, test_signal: bool):
super().__init__(ctx)
self.src = src
self.length = length
self.test_signal = test_signal


I've Tried:

1. 
   Removing @param.context("ctx")
   
   • This fixes the error, but then ctx is not recognized when calling super().__init__(ctx).
2. 
   Replacing @param.context("ctx") with @param.str("ctx")
   
   • This fixes the error, but ctx should not be a string—it's the execution context.
3. 
   Looking for Alternative Context Parameter Declarations
   
   • The Indie documentation mentions MainContext as the base class but doesn't say if ctx needs to be explicitly decorated.

Questions:

1. 
   Is @param.context("ctx") a valid decorator in Indie v4**+**?
   
   
2. 
   If ctx doesn't need to be declared, how do I pass it correctly?
   
   
3. 
   Is there another way to define context-based parameters in Indie?
   

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