I'm trying to utilize the scipy.stats.linregress() function. I double checked that both my inputs are the same size and both are arrays. However I keep getting the following error: Traceback (most recent call last): File "C:/Users/chianh/Desktop/Reliability Py Scripts/MedianRanks_Solver_Rev0.py", line 48, in <module> slope, intercept, r_value, p_value, std_err = stats.linregress(data, median_rank) File "C:\Users\chianh\AppData\Local\Programs\Python\Python35-32\lib\site-packages\scipy\stats\_stats_mstats_common.py", line 81, in linregress r_den = np.sqrt(ssxm * ssym) AttributeError: 'Float' object has no attribute 'sqrt' The code that i wrote is pasted below: import numpy as np import matplotlib.pyplot as plot import scipy.stats as stats from sympy import Symbol, binomial, expand_func, solve, solveset def eval_median_rank( mylist ): P = 0.5 # Percentage Point (would be 0.5 to be median) Z = Symbol('Z', real=True) # Median Rank (Should be solved for each test unit) result = [] # Place holder for the evaluated Median Ranks # Re-iterate and perform for each data point for j in range(1, mylist.size+1): eq = 0 k = j # Generate the Median Rank equation which will be solved for 'Z' or Median Rank while k <= mylist.size: eq = eq + expand_func(binomial(mylist.size, k) * (Z**k) * (1 - Z)**(mylist.size-k)) k += 1 eq = eq - P # Solve for only Median Rank solutions that only fall between 0 and 1. # Then append to the returning list sol = [i for i in solve(eq, Z, list=True) if (i > 0) and (i < 1)] result.extend(sol) result.sort(reverse=True) return np.array(result) ###################################################################################################### # Note that the samples must be ordered in ascending fail-time/UOM, # and the system must be solved in that order. data = np.array([96, 257, 498, 763, 1051, 1744], dtype=object) rank = np.arange(1, data.size+1) median_rank = eval_median_rank(rank) print(median_rank) # Use Scipy's stats package to perform Least-Squares fit slope, intercept, r_value, p_value, std_err = stats.linregress(data, median_rank) Continue reading...